In this Java tutorial, we’ll sort an array in ascending order with a temporary variable and a nested for loop. To get user input, we’re using the Scanner class.

Java Example: Program to Sort an Array in Ascending Order

The user is prompted in this program to enter the number of elements that he wishes to enter. Based on the input, we declared an int array and then accept all of the numbers entered by the user and store them in the array.

• After we’ve stored all of the numbers in the array, we’ll sort them using a nested for loop.

public class JavaExample 
{
    public static void main(String[] args) 
    {
    	int count, temp;
    	
    	//User inputs the array size
        Scanner scan = new Scanner(System.in);
        System.out.print("Enter number of elements you want in the array: ");
        count = scan.nextInt();
    
        int num[] = new int[count];
        System.out.println("Enter array elements:");
        for (int i = 0; i < count; i++) 
        {
            num[i] = scan.nextInt();
        }
        scan.close();
        for (int i = 0; i < count; i++) 
        {
            for (int j = i + 1; j < count; j++) { 
                if (num[i] > num[j]) 
                {
                    temp = num[i];
                    num[i] = num[j];
                    num[j] = temp;
                }
            }
        }
        System.out.print("Array Elements in Ascending Order: ");
        for (int i = 0; i < count - 1; i++) 
        {
            System.out.print(num[i] + ", ");
        }
        System.out.print(num[count - 1]);
    }
}

Output:

Enter number of elements you want in the array: Enter array elements: 100 20 89 -45 78 Array Elements in Ascending Order: -45 20 78 89 100

array is reversed array is reversed array is reversed array is reversed array is reversed array is reversed array is reversed

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