C++ Function Overloading

C++ Function Overloading with Example

In this article, you will learn about what is function overloading in C++ with example.

The ability for two or more functions to have the same name but different parameters is known as function overloading in c++ in object-oriented programming.

Function overloading refers to the overloading of a function name with numerous tasks. When using function overloading, the “Function” name and arguments should match.

  • One example of a polymorphism feature in C++ is function overloading.
  • Multiple functions with the same name may be specified in the same scope in C++.
  • These are referred to as overloads or overloaded functions. With overloaded functions, you can provide a function with a variety of interpretations based on the types and quantities of its arguments.
  • With the help of examples, we will learn about function overloading in C++ in this article.
  • In C++, two functions with different numbers and/or types of arguments can share the same name.

Overloaded functions are those that have the same name but different arguments. For instance:

// same name different arguments
int test() { }
int test(int a) { }
float test(double a) { }
int test(int a, double b) { }

Here, each of the four functions is overloaded.

You’ll see that none of these 4 functions have the same return types. Different return types may or may not be included in overloaded functions, but distinct arguments are a requirement. For instance

The below-given code is not applicable for function overloading:

// Error code
int test(int a) { }
double test(int b){ }

Both of these functions are identical in terms of name, type, and a number of parameters. The compiler will therefore produce an error.

Example 1: Overloading Using Different Types of Parameters

// Program to compute absolute value
// Works for both int and float

#include <iostream>
using namespace std;

// function with float type parameter
float absolute(float var){
    if (var < 0.0)
        var = -var;
    return var;

// function with int type parameter
int absolute(int var) {
     if (var < 0)
         var = -var;
    return var;

int main() {
    // call function with int type parameter
    cout << "Absolute value of -5 = " << absolute(-5) << endl;

    // call function with float type parameter
    cout << "Absolute value of 5.5 = " << absolute(5.5f) << endl;
    return 0;


Absolute value of -5 = 5
Absolute value of 5.5 = 5.5

We overload the absolute() function in this software. The appropriate function is called depending on the kind of parameter given during the function call.

Another Example Of Overloading Using Different Types Of Parameter

#include <iostream>
using namespace std;
class printData {
      void print(int i) {
        cout << "Printing int: " << i << endl;
      void print(double  f) {
        cout << "Printing float: " << f << endl;
      void print(char* c) {
        cout << "Printing character: " << c << endl;

int main(void) {
   printData pd;
   // Call print to print integer
   // Call print to print float
   // Call print to print character
   pd.print("Hello C++");
   return 0;


Printing int: 5
Printing float: 500.263
Printing character: Hello C++

Example 2: Overloading Using Different Number of Parameters

#include <iostream>
using namespace std;

// function with 2 parameters
void display(int var1, double var2) {
    cout << "Integer number: " << var1;
    cout << " and double number: " << var2 << endl;

// function with double type single parameter
void display(double var) {
    cout << "Double number: " << var << endl;

// function with int type single parameter
void display(int var) {
    cout << "Integer number: " << var << endl;

int main() {

    int a = 5;
    double b = 5.5;

    // call function with int type parameter

    // call function with double type parameter

    // call function with 2 parameters
    display(a, b);

    return 0;


Integer number: 5
Float number: 5.5
Integer number: 5 and double number: 5.5

In this case, three calls to the display() function are made with various arguments. The appropriate show() function is called based on the amount and kind of arguments given.

All of these functions have the same return type, however, function overloading does not necessarily need this.

Note: A lot of the standard library functions in C++ are overloaded. The sqrt() function, for instance, accepts double, float, int, etc. as parameters. Due to C++’s overloaded sqrt() method, this is feasible.

Another Example of Overloading Using Different Number of Parameters

using namespace std;

int sum(int a, int b) {
    // function with name sum and,
    // returns sum of two numbers
    return a + b;

int sum(int a, int b, int c) {
    // function with name sum and,
    // returns sum of three numbers
    return a + b + c;

int main() {
    // calculating sum of two numbers
    int sum_1 = sum(5, 10);
    cout<<"5 + 10 = "<<sum_1<<endl;
    // calculating sum of three numbers
    int sum_2 = sum(5, 10, 6);
    cout<<"5 + 10 + 6 = "<<sum_2<<endl;
    return 0;


5 + 10 = 15
5 + 10 + 6 = 21

In this case, the sum() method is used twice with two separate inputs. Depending on how many parameters are supplied during the function call, the matching function sum () is invoked. Sum(), the appropriate function, is invoked.

Note: In this situation, both the sum of the overloaded functions () have the same return type, however, function overloading allows for distinct return values for the overloaded functions.

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This Post Has 3 Comments

  1. ahmed

    cout<<"Absolute value of 5.5="<<absolute(5.5f)<<endl;
    why is there "f" beside 5.5??

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